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Two blocks are connected by a cord on a horizontal surface. A force F pulls on the 15-kg block as shown in the figure. Find the tension in the cord connecting the two blocks to each other if the coefficient of kinetic friction between each block and the ground is 0.2.

----------T=?-------

25KG box-------15kg box-------->F=150N

my work:

(150N)-(0.2)((25kg)(9.8m/s^2)+(15kg)(9.8m/s^2))/(25kg+15kg)=acceleration(A)=1.79m/s^2

T-(0.2)(25kg)(9.8m/s^2)=(25kg)(1.79m/s^2)=T

correct me if i am wrong or tell me if i am right since no one has say anything yet

----------T=?-------

25KG box-------15kg box-------->F=150N

my work:

(150N)-(0.2)((25kg)(9.8m/s^2)+(15kg)(9.8m/s^2))/(25kg+15kg)=acceleration(A)=1.79m/s^2

T-(0.2)(25kg)(9.8m/s^2)=(25kg)(1.79m/s^2)=T

correct me if i am wrong or tell me if i am right since no one has say anything yet

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